Y=4x^2-5x+12

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Solution for Y=4x^2-5x+12 equation: 



=4Y^2-5Y+12

We move all terms to the left:

-(4Y^2-5Y+12)=0

We get rid of parentheses

-4Y^2+5Y-12=0

a = -4; b = 5; c = -12;
Δ = b2-4ac
Δ = 52-4·(-4)·(-12)
Δ = -167
Delta is less than zero, so there is no solution for the equation

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